Q.
f(x) = 56(x) × x!! + 5(x)²
f(9) = ....
✏ RULES :
➠ no kalkulator
➠ pakai cara
➠ no ngasal
➠ rapi ![]()
f(x) = 56(x) × x!! + 5(x)²
f(9) = ....
✏ RULES :
➠ no kalkulator
➠ pakai cara
➠ no ngasal
➠ rapi
f(x) = 56(x) × x!! + 5(x)²
f(9) = 56(9) × 9!! + 5(9)²
f(9) = 504 × ( 9 × 7 × 5 × 3 × 1 ) + 5(81)
f(9) = 504 × 945 + 405
f(9) = 476.280 + 405
f(9) = 476.685
⃢~ Opung~⃠⃫⃟⃤᳗᳐
Jawaban:
f(x) = 56(x) × x!! + 5(x)²
f(9) = 476.685
Pembahasan:
f(x) = 56(x) × x!! + 5(x)²
f(9) = 56(9) × 9!! + 5(9)²
f(9) = 504 × (9×7×5×3×1) + 405
f(9) = 504 × 945 + 405
f(9) = 476.280 + 405
f(9) = 476.685
Detail:
Mapel:Matematika
Kelas:10 - SMA
Materi:Bab 1 - Eksponen dan logaritma
Kata kunci:Eksponen,Faktorial,Bilangan berpangkat
Kode:10.2.1
[answer.2.content]
